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Таблица истинности ONLINE
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Таблица истинности для функции ¬(A∧¬B∧C∨¬A∧C)∨¬A→¬(¬A∧B∨¬C)∨A:
Промежуточные таблицы истинности:¬B: ¬A: A∧(¬B): A | B | ¬B | A∧(¬B) | 0 | 0 | 1 | 0 | 0 | 1 | 0 | 0 | 1 | 0 | 1 | 1 | 1 | 1 | 0 | 0 |
(A∧(¬B))∧C: A | B | C | ¬B | A∧(¬B) | (A∧(¬B))∧C | 0 | 0 | 0 | 1 | 0 | 0 | 0 | 0 | 1 | 1 | 0 | 0 | 0 | 1 | 0 | 0 | 0 | 0 | 0 | 1 | 1 | 0 | 0 | 0 | 1 | 0 | 0 | 1 | 1 | 0 | 1 | 0 | 1 | 1 | 1 | 1 | 1 | 1 | 0 | 0 | 0 | 0 | 1 | 1 | 1 | 0 | 0 | 0 |
(¬A)∧C: A | C | ¬A | (¬A)∧C | 0 | 0 | 1 | 0 | 0 | 1 | 1 | 1 | 1 | 0 | 0 | 0 | 1 | 1 | 0 | 0 |
((A∧(¬B))∧C)∨((¬A)∧C): A | B | C | ¬B | A∧(¬B) | (A∧(¬B))∧C | ¬A | (¬A)∧C | ((A∧(¬B))∧C)∨((¬A)∧C) | 0 | 0 | 0 | 1 | 0 | 0 | 1 | 0 | 0 | 0 | 0 | 1 | 1 | 0 | 0 | 1 | 1 | 1 | 0 | 1 | 0 | 0 | 0 | 0 | 1 | 0 | 0 | 0 | 1 | 1 | 0 | 0 | 0 | 1 | 1 | 1 | 1 | 0 | 0 | 1 | 1 | 0 | 0 | 0 | 0 | 1 | 0 | 1 | 1 | 1 | 1 | 0 | 0 | 1 | 1 | 1 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 1 | 1 | 1 | 0 | 0 | 0 | 0 | 0 | 0 |
¬C: (¬A)∧B: A | B | ¬A | (¬A)∧B | 0 | 0 | 1 | 0 | 0 | 1 | 1 | 1 | 1 | 0 | 0 | 0 | 1 | 1 | 0 | 0 |
((¬A)∧B)∨(¬C): A | B | C | ¬A | (¬A)∧B | ¬C | ((¬A)∧B)∨(¬C) | 0 | 0 | 0 | 1 | 0 | 1 | 1 | 0 | 0 | 1 | 1 | 0 | 0 | 0 | 0 | 1 | 0 | 1 | 1 | 1 | 1 | 0 | 1 | 1 | 1 | 1 | 0 | 1 | 1 | 0 | 0 | 0 | 0 | 1 | 1 | 1 | 0 | 1 | 0 | 0 | 0 | 0 | 1 | 1 | 0 | 0 | 0 | 1 | 1 | 1 | 1 | 1 | 0 | 0 | 0 | 0 |
¬(((A∧(¬B))∧C)∨((¬A)∧C)): A | B | C | ¬B | A∧(¬B) | (A∧(¬B))∧C | ¬A | (¬A)∧C | ((A∧(¬B))∧C)∨((¬A)∧C) | ¬(((A∧(¬B))∧C)∨((¬A)∧C)) | 0 | 0 | 0 | 1 | 0 | 0 | 1 | 0 | 0 | 1 | 0 | 0 | 1 | 1 | 0 | 0 | 1 | 1 | 1 | 0 | 0 | 1 | 0 | 0 | 0 | 0 | 1 | 0 | 0 | 1 | 0 | 1 | 1 | 0 | 0 | 0 | 1 | 1 | 1 | 0 | 1 | 0 | 0 | 1 | 1 | 0 | 0 | 0 | 0 | 1 | 1 | 0 | 1 | 1 | 1 | 1 | 0 | 0 | 1 | 0 | 1 | 1 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 1 | 1 | 1 | 1 | 0 | 0 | 0 | 0 | 0 | 0 | 1 |
¬(((¬A)∧B)∨(¬C)): A | B | C | ¬A | (¬A)∧B | ¬C | ((¬A)∧B)∨(¬C) | ¬(((¬A)∧B)∨(¬C)) | 0 | 0 | 0 | 1 | 0 | 1 | 1 | 0 | 0 | 0 | 1 | 1 | 0 | 0 | 0 | 1 | 0 | 1 | 0 | 1 | 1 | 1 | 1 | 0 | 0 | 1 | 1 | 1 | 1 | 0 | 1 | 0 | 1 | 0 | 0 | 0 | 0 | 1 | 1 | 0 | 1 | 0 | 1 | 0 | 0 | 0 | 0 | 1 | 1 | 1 | 0 | 0 | 0 | 1 | 1 | 0 | 1 | 1 | 1 | 0 | 0 | 0 | 0 | 1 |
(¬(((A∧(¬B))∧C)∨((¬A)∧C)))∨(¬A): A | B | C | ¬B | A∧(¬B) | (A∧(¬B))∧C | ¬A | (¬A)∧C | ((A∧(¬B))∧C)∨((¬A)∧C) | ¬(((A∧(¬B))∧C)∨((¬A)∧C)) | ¬A | (¬(((A∧(¬B))∧C)∨((¬A)∧C)))∨(¬A) | 0 | 0 | 0 | 1 | 0 | 0 | 1 | 0 | 0 | 1 | 1 | 1 | 0 | 0 | 1 | 1 | 0 | 0 | 1 | 1 | 1 | 0 | 1 | 1 | 0 | 1 | 0 | 0 | 0 | 0 | 1 | 0 | 0 | 1 | 1 | 1 | 0 | 1 | 1 | 0 | 0 | 0 | 1 | 1 | 1 | 0 | 1 | 1 | 1 | 0 | 0 | 1 | 1 | 0 | 0 | 0 | 0 | 1 | 0 | 1 | 1 | 0 | 1 | 1 | 1 | 1 | 0 | 0 | 1 | 0 | 0 | 0 | 1 | 1 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 1 | 0 | 1 | 1 | 1 | 1 | 0 | 0 | 0 | 0 | 0 | 0 | 1 | 0 | 1 |
(¬(((¬A)∧B)∨(¬C)))∨A: A | B | C | ¬A | (¬A)∧B | ¬C | ((¬A)∧B)∨(¬C) | ¬(((¬A)∧B)∨(¬C)) | (¬(((¬A)∧B)∨(¬C)))∨A | 0 | 0 | 0 | 1 | 0 | 1 | 1 | 0 | 0 | 0 | 0 | 1 | 1 | 0 | 0 | 0 | 1 | 1 | 0 | 1 | 0 | 1 | 1 | 1 | 1 | 0 | 0 | 0 | 1 | 1 | 1 | 1 | 0 | 1 | 0 | 0 | 1 | 0 | 0 | 0 | 0 | 1 | 1 | 0 | 1 | 1 | 0 | 1 | 0 | 0 | 0 | 0 | 1 | 1 | 1 | 1 | 0 | 0 | 0 | 1 | 1 | 0 | 1 | 1 | 1 | 1 | 0 | 0 | 0 | 0 | 1 | 1 |
((¬(((A∧(¬B))∧C)∨((¬A)∧C)))∨(¬A))→((¬(((¬A)∧B)∨(¬C)))∨A): A | B | C | ¬B | A∧(¬B) | (A∧(¬B))∧C | ¬A | (¬A)∧C | ((A∧(¬B))∧C)∨((¬A)∧C) | ¬(((A∧(¬B))∧C)∨((¬A)∧C)) | ¬A | (¬(((A∧(¬B))∧C)∨((¬A)∧C)))∨(¬A) | ¬A | (¬A)∧B | ¬C | ((¬A)∧B)∨(¬C) | ¬(((¬A)∧B)∨(¬C)) | (¬(((¬A)∧B)∨(¬C)))∨A | ((¬(((A∧(¬B))∧C)∨((¬A)∧C)))∨(¬A))→((¬(((¬A)∧B)∨(¬C)))∨A) | 0 | 0 | 0 | 1 | 0 | 0 | 1 | 0 | 0 | 1 | 1 | 1 | 1 | 0 | 1 | 1 | 0 | 0 | 0 | 0 | 0 | 1 | 1 | 0 | 0 | 1 | 1 | 1 | 0 | 1 | 1 | 1 | 0 | 0 | 0 | 1 | 1 | 1 | 0 | 1 | 0 | 0 | 0 | 0 | 1 | 0 | 0 | 1 | 1 | 1 | 1 | 1 | 1 | 1 | 0 | 0 | 0 | 0 | 1 | 1 | 0 | 0 | 0 | 1 | 1 | 1 | 0 | 1 | 1 | 1 | 1 | 0 | 1 | 0 | 0 | 0 | 1 | 0 | 0 | 1 | 1 | 0 | 0 | 0 | 0 | 1 | 0 | 1 | 0 | 0 | 1 | 1 | 0 | 1 | 1 | 1 | 0 | 1 | 1 | 1 | 1 | 0 | 0 | 1 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 1 | 1 | 1 | 1 | 1 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 1 | 0 | 1 | 0 | 0 | 1 | 1 | 0 | 1 | 1 | 1 | 1 | 1 | 0 | 0 | 0 | 0 | 0 | 0 | 1 | 0 | 1 | 0 | 0 | 0 | 0 | 1 | 1 | 1 |
Общая таблица истинности:A | B | C | ¬B | ¬A | A∧(¬B) | (A∧(¬B))∧C | (¬A)∧C | ((A∧(¬B))∧C)∨((¬A)∧C) | ¬C | (¬A)∧B | ((¬A)∧B)∨(¬C) | ¬(((A∧(¬B))∧C)∨((¬A)∧C)) | ¬(((¬A)∧B)∨(¬C)) | (¬(((A∧(¬B))∧C)∨((¬A)∧C)))∨(¬A) | (¬(((¬A)∧B)∨(¬C)))∨A | ¬(A∧¬B∧C∨¬A∧C)∨¬A→¬(¬A∧B∨¬C)∨A | 0 | 0 | 0 | 1 | 1 | 0 | 0 | 0 | 0 | 1 | 0 | 1 | 1 | 0 | 1 | 0 | 0 | 0 | 0 | 1 | 1 | 1 | 0 | 0 | 1 | 1 | 0 | 0 | 0 | 0 | 1 | 1 | 1 | 1 | 0 | 1 | 0 | 0 | 1 | 0 | 0 | 0 | 0 | 1 | 1 | 1 | 1 | 0 | 1 | 0 | 0 | 0 | 1 | 1 | 0 | 1 | 0 | 0 | 1 | 1 | 0 | 1 | 1 | 0 | 0 | 1 | 0 | 0 | 1 | 0 | 0 | 1 | 0 | 1 | 0 | 0 | 0 | 1 | 0 | 1 | 1 | 0 | 1 | 1 | 1 | 1 | 0 | 1 | 1 | 0 | 1 | 1 | 0 | 1 | 0 | 0 | 0 | 0 | 1 | 0 | 1 | 1 | 1 | 1 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 1 | 0 | 1 | 1 | 0 | 1 | 1 | 1 | 1 | 1 | 1 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 1 | 1 | 1 | 1 | 1 |
Логическая схема:
Совершенная дизъюнктивная нормальная форма (СДНФ):
По таблице истинности: A | B | C | F | 0 | 0 | 0 | 0 | 0 | 0 | 1 | 1 | 0 | 1 | 0 | 0 | 0 | 1 | 1 | 0 | 1 | 0 | 0 | 1 | 1 | 0 | 1 | 1 | 1 | 1 | 0 | 1 | 1 | 1 | 1 | 1 |
F сднф = ¬A∧¬B∧C ∨ A∧¬B∧¬C ∨ A∧¬B∧C ∨ A∧B∧¬C ∨ A∧B∧C Логическая cхема:
Совершенная конъюнктивная нормальная форма (СКНФ):
По таблице истинности: A | B | C | F | 0 | 0 | 0 | 0 | 0 | 0 | 1 | 1 | 0 | 1 | 0 | 0 | 0 | 1 | 1 | 0 | 1 | 0 | 0 | 1 | 1 | 0 | 1 | 1 | 1 | 1 | 0 | 1 | 1 | 1 | 1 | 1 |
F скнф = (A∨B∨C) ∧ (A∨¬B∨C) ∧ (A∨¬B∨¬C) Логическая cхема:
Построение полинома Жегалкина:
По таблице истинности функции A | B | C | Fж | 0 | 0 | 0 | 0 | 0 | 0 | 1 | 1 | 0 | 1 | 0 | 0 | 0 | 1 | 1 | 0 | 1 | 0 | 0 | 1 | 1 | 0 | 1 | 1 | 1 | 1 | 0 | 1 | 1 | 1 | 1 | 1 |
Построим полином Жегалкина: F ж = C 000 ⊕ C 100∧A ⊕ C 010∧B ⊕ C 001∧C ⊕ C 110∧A∧B ⊕ C 101∧A∧C ⊕ C 011∧B∧C ⊕ C 111∧A∧B∧C Так как F ж(000) = 0, то С 000 = 0. Далее подставляем все остальные наборы в порядке возрастания числа единиц, подставляя вновь полученные значения в следующие формулы: F ж(100) = С 000 ⊕ С 100 = 1 => С 100 = 0 ⊕ 1 = 1 F ж(010) = С 000 ⊕ С 010 = 0 => С 010 = 0 ⊕ 0 = 0 F ж(001) = С 000 ⊕ С 001 = 1 => С 001 = 0 ⊕ 1 = 1 F ж(110) = С 000 ⊕ С 100 ⊕ С 010 ⊕ С 110 = 1 => С 110 = 0 ⊕ 1 ⊕ 0 ⊕ 1 = 0 F ж(101) = С 000 ⊕ С 100 ⊕ С 001 ⊕ С 101 = 1 => С 101 = 0 ⊕ 1 ⊕ 1 ⊕ 1 = 1 F ж(011) = С 000 ⊕ С 010 ⊕ С 001 ⊕ С 011 = 0 => С 011 = 0 ⊕ 0 ⊕ 1 ⊕ 0 = 1 F ж(111) = С 000 ⊕ С 100 ⊕ С 010 ⊕ С 001 ⊕ С 110 ⊕ С 101 ⊕ С 011 ⊕ С 111 = 1 => С 111 = 0 ⊕ 1 ⊕ 0 ⊕ 1 ⊕ 0 ⊕ 1 ⊕ 1 ⊕ 1 = 1 Таким образом, полином Жегалкина будет равен: F ж = A ⊕ C ⊕ A∧C ⊕ B∧C ⊕ A∧B∧C Логическая схема, соответствующая полиному Жегалкина:
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