Таблица истинности для функции ¬X1∧¬X2∧¬X3∨¬X1∧¬X2∧X4∨0∨X1∧¬X3∧X4∨X1∧X3∧¬(X2∧X4):


Общая таблица истинности:

X1X2X3X4X2∧X4¬X1¬X2¬X3¬(X2∧X4)(¬X1)∧(¬X2)((¬X1)∧(¬X2))∧(¬X3)((¬X1)∧(¬X2))∧X4X1∧(¬X3)(X1∧(¬X3))∧X4X1∧X3(X1∧X3)∧(¬(X2∧X4))(((¬X1)∧(¬X2))∧(¬X3))∨(((¬X1)∧(¬X2))∧X4)((((¬X1)∧(¬X2))∧(¬X3))∨(((¬X1)∧(¬X2))∧X4))∨0(((((¬X1)∧(¬X2))∧(¬X3))∨(((¬X1)∧(¬X2))∧X4))∨0)∨((X1∧(¬X3))∧X4)¬X1∧¬X2∧¬X3∨¬X1∧¬X2∧X4∨0∨X1∧¬X3∧X4∨X1∧X3∧¬(X2∧X4)
00000111111000001111
00010111111100001111
00100110110000000000
00110110110100001111
01000101100000000000
01011101000000000000
01100100100000000000
01111100000000000000
10000011100010000000
10010011100011000011
10100010100000110001
10110010100000110001
11000001100010000000
11011001000011000011
11100000100000110001
11111000000000100000


Построение полинома Жегалкина:

По таблице истинности функции
X1X2X3X4Fж
00001
00011
00100
00111
01000
01010
01100
01110
10000
10011
10101
10111
11000
11011
11101
11110

Построим полином Жегалкина:
Fж = C0000 ⊕ C1000∧X1 ⊕ C0100∧X2 ⊕ C0010∧X3 ⊕ C0001∧X4 ⊕ C1100∧X1∧X2 ⊕ C1010∧X1∧X3 ⊕ C1001∧X1∧X4 ⊕ C0110∧X2∧X3 ⊕ C0101∧X2∧X4 ⊕ C0011∧X3∧X4 ⊕ C1110∧X1∧X2∧X3 ⊕ C1101∧X1∧X2∧X4 ⊕ C1011∧X1∧X3∧X4 ⊕ C0111∧X2∧X3∧X4 ⊕ C1111∧X1∧X2∧X3∧X4

Так как Fж(0000) = 1, то С0000 = 1.

Далее подставляем все остальные наборы в порядке возрастания числа единиц, подставляя вновь полученные значения в следующие формулы:
Fж(1000) = С0000 ⊕ С1000 = 0 => С1000 = 1 ⊕ 0 = 1
Fж(0100) = С0000 ⊕ С0100 = 0 => С0100 = 1 ⊕ 0 = 1
Fж(0010) = С0000 ⊕ С0010 = 0 => С0010 = 1 ⊕ 0 = 1
Fж(0001) = С0000 ⊕ С0001 = 1 => С0001 = 1 ⊕ 1 = 0
Fж(1100) = С0000 ⊕ С1000 ⊕ С0100 ⊕ С1100 = 0 => С1100 = 1 ⊕ 1 ⊕ 1 ⊕ 0 = 1
Fж(1010) = С0000 ⊕ С1000 ⊕ С0010 ⊕ С1010 = 1 => С1010 = 1 ⊕ 1 ⊕ 1 ⊕ 1 = 0
Fж(1001) = С0000 ⊕ С1000 ⊕ С0001 ⊕ С1001 = 1 => С1001 = 1 ⊕ 1 ⊕ 0 ⊕ 1 = 1
Fж(0110) = С0000 ⊕ С0100 ⊕ С0010 ⊕ С0110 = 0 => С0110 = 1 ⊕ 1 ⊕ 1 ⊕ 0 = 1
Fж(0101) = С0000 ⊕ С0100 ⊕ С0001 ⊕ С0101 = 0 => С0101 = 1 ⊕ 1 ⊕ 0 ⊕ 0 = 0
Fж(0011) = С0000 ⊕ С0010 ⊕ С0001 ⊕ С0011 = 1 => С0011 = 1 ⊕ 1 ⊕ 0 ⊕ 1 = 1
Fж(1110) = С0000 ⊕ С1000 ⊕ С0100 ⊕ С0010 ⊕ С1100 ⊕ С1010 ⊕ С0110 ⊕ С1110 = 1 => С1110 = 1 ⊕ 1 ⊕ 1 ⊕ 1 ⊕ 1 ⊕ 0 ⊕ 1 ⊕ 1 = 1
Fж(1101) = С0000 ⊕ С1000 ⊕ С0100 ⊕ С0001 ⊕ С1100 ⊕ С1001 ⊕ С0101 ⊕ С1101 = 1 => С1101 = 1 ⊕ 1 ⊕ 1 ⊕ 0 ⊕ 1 ⊕ 1 ⊕ 0 ⊕ 1 = 0
Fж(1011) = С0000 ⊕ С1000 ⊕ С0010 ⊕ С0001 ⊕ С1010 ⊕ С1001 ⊕ С0011 ⊕ С1011 = 1 => С1011 = 1 ⊕ 1 ⊕ 1 ⊕ 0 ⊕ 0 ⊕ 1 ⊕ 1 ⊕ 1 = 0
Fж(0111) = С0000 ⊕ С0100 ⊕ С0010 ⊕ С0001 ⊕ С0110 ⊕ С0101 ⊕ С0011 ⊕ С0111 = 0 => С0111 = 1 ⊕ 1 ⊕ 1 ⊕ 0 ⊕ 1 ⊕ 0 ⊕ 1 ⊕ 0 = 1
Fж(1111) = С0000 ⊕ С1000 ⊕ С0100 ⊕ С0010 ⊕ С0001 ⊕ С1100 ⊕ С1010 ⊕ С1001 ⊕ С0110 ⊕ С0101 ⊕ С0011 ⊕ С1110 ⊕ С1101 ⊕ С1011 ⊕ С0111 ⊕ С1111 = 0 => С1111 = 1 ⊕ 1 ⊕ 1 ⊕ 1 ⊕ 0 ⊕ 1 ⊕ 0 ⊕ 1 ⊕ 1 ⊕ 0 ⊕ 1 ⊕ 1 ⊕ 0 ⊕ 0 ⊕ 1 ⊕ 0 = 0

Таким образом, полином Жегалкина будет равен:
Fж = 1 ⊕ X1 ⊕ X2 ⊕ X3 ⊕ X1∧X2 ⊕ X1∧X4 ⊕ X2∧X3 ⊕ X3∧X4 ⊕ X1∧X2∧X3 ⊕ X2∧X3∧X4

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