Таблица истинности для функции (W∧¬X∧¬Y)∨(W∧X∧Y)∨(¬W∧Y∧Z)∨(W∧Y∧¬Z):


Общая таблица истинности:

WXYZ¬X¬YW∧(¬X)(W∧(¬X))∧(¬Y)W∧X(W∧X)∧Y¬W(¬W)∧Y((¬W)∧Y)∧Z¬ZW∧Y(W∧Y)∧(¬Z)((W∧(¬X))∧(¬Y))∨((W∧X)∧Y)(((W∧(¬X))∧(¬Y))∨((W∧X)∧Y))∨(((¬W)∧Y)∧Z)(W∧¬X∧¬Y)∨(W∧X∧Y)∨(¬W∧Y∧Z)∨(W∧Y∧¬Z)
0000110000100100000
0001110000100000000
0010100000110100000
0011100000111000011
0100010000100100000
0101010000100000000
0110000000110100000
0111000000111000011
1000111100000100111
1001111100000000111
1010101000000111001
1011101000000010000
1100010010000100000
1101010010000000000
1110000011000111111
1111000011000010111


Построение полинома Жегалкина:

По таблице истинности функции
WXYZFж
00000
00010
00100
00111
01000
01010
01100
01111
10001
10011
10101
10110
11000
11010
11101
11111

Построим полином Жегалкина:
Fж = C0000 ⊕ C1000∧W ⊕ C0100∧X ⊕ C0010∧Y ⊕ C0001∧Z ⊕ C1100∧W∧X ⊕ C1010∧W∧Y ⊕ C1001∧W∧Z ⊕ C0110∧X∧Y ⊕ C0101∧X∧Z ⊕ C0011∧Y∧Z ⊕ C1110∧W∧X∧Y ⊕ C1101∧W∧X∧Z ⊕ C1011∧W∧Y∧Z ⊕ C0111∧X∧Y∧Z ⊕ C1111∧W∧X∧Y∧Z

Так как Fж(0000) = 0, то С0000 = 0.

Далее подставляем все остальные наборы в порядке возрастания числа единиц, подставляя вновь полученные значения в следующие формулы:
Fж(1000) = С0000 ⊕ С1000 = 1 => С1000 = 0 ⊕ 1 = 1
Fж(0100) = С0000 ⊕ С0100 = 0 => С0100 = 0 ⊕ 0 = 0
Fж(0010) = С0000 ⊕ С0010 = 0 => С0010 = 0 ⊕ 0 = 0
Fж(0001) = С0000 ⊕ С0001 = 0 => С0001 = 0 ⊕ 0 = 0
Fж(1100) = С0000 ⊕ С1000 ⊕ С0100 ⊕ С1100 = 0 => С1100 = 0 ⊕ 1 ⊕ 0 ⊕ 0 = 1
Fж(1010) = С0000 ⊕ С1000 ⊕ С0010 ⊕ С1010 = 1 => С1010 = 0 ⊕ 1 ⊕ 0 ⊕ 1 = 0
Fж(1001) = С0000 ⊕ С1000 ⊕ С0001 ⊕ С1001 = 1 => С1001 = 0 ⊕ 1 ⊕ 0 ⊕ 1 = 0
Fж(0110) = С0000 ⊕ С0100 ⊕ С0010 ⊕ С0110 = 0 => С0110 = 0 ⊕ 0 ⊕ 0 ⊕ 0 = 0
Fж(0101) = С0000 ⊕ С0100 ⊕ С0001 ⊕ С0101 = 0 => С0101 = 0 ⊕ 0 ⊕ 0 ⊕ 0 = 0
Fж(0011) = С0000 ⊕ С0010 ⊕ С0001 ⊕ С0011 = 1 => С0011 = 0 ⊕ 0 ⊕ 0 ⊕ 1 = 1
Fж(1110) = С0000 ⊕ С1000 ⊕ С0100 ⊕ С0010 ⊕ С1100 ⊕ С1010 ⊕ С0110 ⊕ С1110 = 1 => С1110 = 0 ⊕ 1 ⊕ 0 ⊕ 0 ⊕ 1 ⊕ 0 ⊕ 0 ⊕ 1 = 1
Fж(1101) = С0000 ⊕ С1000 ⊕ С0100 ⊕ С0001 ⊕ С1100 ⊕ С1001 ⊕ С0101 ⊕ С1101 = 0 => С1101 = 0 ⊕ 1 ⊕ 0 ⊕ 0 ⊕ 1 ⊕ 0 ⊕ 0 ⊕ 0 = 0
Fж(1011) = С0000 ⊕ С1000 ⊕ С0010 ⊕ С0001 ⊕ С1010 ⊕ С1001 ⊕ С0011 ⊕ С1011 = 0 => С1011 = 0 ⊕ 1 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 1 ⊕ 0 = 0
Fж(0111) = С0000 ⊕ С0100 ⊕ С0010 ⊕ С0001 ⊕ С0110 ⊕ С0101 ⊕ С0011 ⊕ С0111 = 1 => С0111 = 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 1 ⊕ 1 = 0
Fж(1111) = С0000 ⊕ С1000 ⊕ С0100 ⊕ С0010 ⊕ С0001 ⊕ С1100 ⊕ С1010 ⊕ С1001 ⊕ С0110 ⊕ С0101 ⊕ С0011 ⊕ С1110 ⊕ С1101 ⊕ С1011 ⊕ С0111 ⊕ С1111 = 1 => С1111 = 0 ⊕ 1 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 1 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 1 ⊕ 1 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 1 = 1

Таким образом, полином Жегалкина будет равен:
Fж = W ⊕ W∧X ⊕ Y∧Z ⊕ W∧X∧Y ⊕ W∧X∧Y∧Z

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