Таблица истинности для функции A∧B∧C∧¬(D∧E∧F):


Промежуточные таблицы истинности:
D∧E:
DED∧E
000
010
100
111

(D∧E)∧F:
DEFD∧E(D∧E)∧F
00000
00100
01000
01100
10000
10100
11010
11111

¬((D∧E)∧F):
DEFD∧E(D∧E)∧F¬((D∧E)∧F)
000001
001001
010001
011001
100001
101001
110101
111110

A∧B:
ABA∧B
000
010
100
111

(A∧B)∧C:
ABCA∧B(A∧B)∧C
00000
00100
01000
01100
10000
10100
11010
11111

((A∧B)∧C)∧(¬((D∧E)∧F)):
ABCDEFA∧B(A∧B)∧CD∧E(D∧E)∧F¬((D∧E)∧F)((A∧B)∧C)∧(¬((D∧E)∧F))
000000000010
000001000010
000010000010
000011000010
000100000010
000101000010
000110001010
000111001100
001000000010
001001000010
001010000010
001011000010
001100000010
001101000010
001110001010
001111001100
010000000010
010001000010
010010000010
010011000010
010100000010
010101000010
010110001010
010111001100
011000000010
011001000010
011010000010
011011000010
011100000010
011101000010
011110001010
011111001100
100000000010
100001000010
100010000010
100011000010
100100000010
100101000010
100110001010
100111001100
101000000010
101001000010
101010000010
101011000010
101100000010
101101000010
101110001010
101111001100
110000100010
110001100010
110010100010
110011100010
110100100010
110101100010
110110101010
110111101100
111000110011
111001110011
111010110011
111011110011
111100110011
111101110011
111110111011
111111111100

Общая таблица истинности:

ABCDEFD∧E(D∧E)∧F¬((D∧E)∧F)A∧B(A∧B)∧CA∧B∧C∧¬(D∧E∧F)
000000001000
000001001000
000010001000
000011001000
000100001000
000101001000
000110101000
000111110000
001000001000
001001001000
001010001000
001011001000
001100001000
001101001000
001110101000
001111110000
010000001000
010001001000
010010001000
010011001000
010100001000
010101001000
010110101000
010111110000
011000001000
011001001000
011010001000
011011001000
011100001000
011101001000
011110101000
011111110000
100000001000
100001001000
100010001000
100011001000
100100001000
100101001000
100110101000
100111110000
101000001000
101001001000
101010001000
101011001000
101100001000
101101001000
101110101000
101111110000
110000001100
110001001100
110010001100
110011001100
110100001100
110101001100
110110101100
110111110100
111000001111
111001001111
111010001111
111011001111
111100001111
111101001111
111110101111
111111110110

Логическая схема:

Совершенная дизъюнктивная нормальная форма (СДНФ):

По таблице истинности:
ABCDEFF
0000000
0000010
0000100
0000110
0001000
0001010
0001100
0001110
0010000
0010010
0010100
0010110
0011000
0011010
0011100
0011110
0100000
0100010
0100100
0100110
0101000
0101010
0101100
0101110
0110000
0110010
0110100
0110110
0111000
0111010
0111100
0111110
1000000
1000010
1000100
1000110
1001000
1001010
1001100
1001110
1010000
1010010
1010100
1010110
1011000
1011010
1011100
1011110
1100000
1100010
1100100
1100110
1101000
1101010
1101100
1101110
1110001
1110011
1110101
1110111
1111001
1111011
1111101
1111110
Fсднф = A∧B∧C∧¬D∧¬E∧¬F ∨ A∧B∧C∧¬D∧¬E∧F ∨ A∧B∧C∧¬D∧E∧¬F ∨ A∧B∧C∧¬D∧E∧F ∨ A∧B∧C∧D∧¬E∧¬F ∨ A∧B∧C∧D∧¬E∧F ∨ A∧B∧C∧D∧E∧¬F
Логическая cхема:

Совершенная конъюнктивная нормальная форма (СКНФ):

По таблице истинности:
ABCDEFF
0000000
0000010
0000100
0000110
0001000
0001010
0001100
0001110
0010000
0010010
0010100
0010110
0011000
0011010
0011100
0011110
0100000
0100010
0100100
0100110
0101000
0101010
0101100
0101110
0110000
0110010
0110100
0110110
0111000
0111010
0111100
0111110
1000000
1000010
1000100
1000110
1001000
1001010
1001100
1001110
1010000
1010010
1010100
1010110
1011000
1011010
1011100
1011110
1100000
1100010
1100100
1100110
1101000
1101010
1101100
1101110
1110001
1110011
1110101
1110111
1111001
1111011
1111101
1111110
Fскнф = (A∨B∨C∨D∨E∨F) ∧ (A∨B∨C∨D∨E∨¬F) ∧ (A∨B∨C∨D∨¬E∨F) ∧ (A∨B∨C∨D∨¬E∨¬F) ∧ (A∨B∨C∨¬D∨E∨F) ∧ (A∨B∨C∨¬D∨E∨¬F) ∧ (A∨B∨C∨¬D∨¬E∨F) ∧ (A∨B∨C∨¬D∨¬E∨¬F) ∧ (A∨B∨¬C∨D∨E∨F) ∧ (A∨B∨¬C∨D∨E∨¬F) ∧ (A∨B∨¬C∨D∨¬E∨F) ∧ (A∨B∨¬C∨D∨¬E∨¬F) ∧ (A∨B∨¬C∨¬D∨E∨F) ∧ (A∨B∨¬C∨¬D∨E∨¬F) ∧ (A∨B∨¬C∨¬D∨¬E∨F) ∧ (A∨B∨¬C∨¬D∨¬E∨¬F) ∧ (A∨¬B∨C∨D∨E∨F) ∧ (A∨¬B∨C∨D∨E∨¬F) ∧ (A∨¬B∨C∨D∨¬E∨F) ∧ (A∨¬B∨C∨D∨¬E∨¬F) ∧ (A∨¬B∨C∨¬D∨E∨F) ∧ (A∨¬B∨C∨¬D∨E∨¬F) ∧ (A∨¬B∨C∨¬D∨¬E∨F) ∧ (A∨¬B∨C∨¬D∨¬E∨¬F) ∧ (A∨¬B∨¬C∨D∨E∨F) ∧ (A∨¬B∨¬C∨D∨E∨¬F) ∧ (A∨¬B∨¬C∨D∨¬E∨F) ∧ (A∨¬B∨¬C∨D∨¬E∨¬F) ∧ (A∨¬B∨¬C∨¬D∨E∨F) ∧ (A∨¬B∨¬C∨¬D∨E∨¬F) ∧ (A∨¬B∨¬C∨¬D∨¬E∨F) ∧ (A∨¬B∨¬C∨¬D∨¬E∨¬F) ∧ (¬A∨B∨C∨D∨E∨F) ∧ (¬A∨B∨C∨D∨E∨¬F) ∧ (¬A∨B∨C∨D∨¬E∨F) ∧ (¬A∨B∨C∨D∨¬E∨¬F) ∧ (¬A∨B∨C∨¬D∨E∨F) ∧ (¬A∨B∨C∨¬D∨E∨¬F) ∧ (¬A∨B∨C∨¬D∨¬E∨F) ∧ (¬A∨B∨C∨¬D∨¬E∨¬F) ∧ (¬A∨B∨¬C∨D∨E∨F) ∧ (¬A∨B∨¬C∨D∨E∨¬F) ∧ (¬A∨B∨¬C∨D∨¬E∨F) ∧ (¬A∨B∨¬C∨D∨¬E∨¬F) ∧ (¬A∨B∨¬C∨¬D∨E∨F) ∧ (¬A∨B∨¬C∨¬D∨E∨¬F) ∧ (¬A∨B∨¬C∨¬D∨¬E∨F) ∧ (¬A∨B∨¬C∨¬D∨¬E∨¬F) ∧ (¬A∨¬B∨C∨D∨E∨F) ∧ (¬A∨¬B∨C∨D∨E∨¬F) ∧ (¬A∨¬B∨C∨D∨¬E∨F) ∧ (¬A∨¬B∨C∨D∨¬E∨¬F) ∧ (¬A∨¬B∨C∨¬D∨E∨F) ∧ (¬A∨¬B∨C∨¬D∨E∨¬F) ∧ (¬A∨¬B∨C∨¬D∨¬E∨F) ∧ (¬A∨¬B∨C∨¬D∨¬E∨¬F) ∧ (¬A∨¬B∨¬C∨¬D∨¬E∨¬F)
Логическая cхема:

Построение полинома Жегалкина:

По таблице истинности функции
ABCDEFFж
0000000
0000010
0000100
0000110
0001000
0001010
0001100
0001110
0010000
0010010
0010100
0010110
0011000
0011010
0011100
0011110
0100000
0100010
0100100
0100110
0101000
0101010
0101100
0101110
0110000
0110010
0110100
0110110
0111000
0111010
0111100
0111110
1000000
1000010
1000100
1000110
1001000
1001010
1001100
1001110
1010000
1010010
1010100
1010110
1011000
1011010
1011100
1011110
1100000
1100010
1100100
1100110
1101000
1101010
1101100
1101110
1110001
1110011
1110101
1110111
1111001
1111011
1111101
1111110

Построим полином Жегалкина:
Fж = C000000 ⊕ C100000∧A ⊕ C010000∧B ⊕ C001000∧C ⊕ C000100∧D ⊕ C000010∧E ⊕ C000001∧F ⊕ C110000∧A∧B ⊕ C101000∧A∧C ⊕ C100100∧A∧D ⊕ C100010∧A∧E ⊕ C100001∧A∧F ⊕ C011000∧B∧C ⊕ C010100∧B∧D ⊕ C010010∧B∧E ⊕ C010001∧B∧F ⊕ C001100∧C∧D ⊕ C001010∧C∧E ⊕ C001001∧C∧F ⊕ C000110∧D∧E ⊕ C000101∧D∧F ⊕ C000011∧E∧F ⊕ C111000∧A∧B∧C ⊕ C110100∧A∧B∧D ⊕ C110010∧A∧B∧E ⊕ C110001∧A∧B∧F ⊕ C101100∧A∧C∧D ⊕ C101010∧A∧C∧E ⊕ C101001∧A∧C∧F ⊕ C100110∧A∧D∧E ⊕ C100101∧A∧D∧F ⊕ C100011∧A∧E∧F ⊕ C011100∧B∧C∧D ⊕ C011010∧B∧C∧E ⊕ C011001∧B∧C∧F ⊕ C010110∧B∧D∧E ⊕ C010101∧B∧D∧F ⊕ C010011∧B∧E∧F ⊕ C001110∧C∧D∧E ⊕ C001101∧C∧D∧F ⊕ C001011∧C∧E∧F ⊕ C000111∧D∧E∧F ⊕ C111100∧A∧B∧C∧D ⊕ C111010∧A∧B∧C∧E ⊕ C111001∧A∧B∧C∧F ⊕ C110110∧A∧B∧D∧E ⊕ C110101∧A∧B∧D∧F ⊕ C110011∧A∧B∧E∧F ⊕ C101110∧A∧C∧D∧E ⊕ C101101∧A∧C∧D∧F ⊕ C101011∧A∧C∧E∧F ⊕ C100111∧A∧D∧E∧F ⊕ C011110∧B∧C∧D∧E ⊕ C011101∧B∧C∧D∧F ⊕ C011011∧B∧C∧E∧F ⊕ C010111∧B∧D∧E∧F ⊕ C001111∧C∧D∧E∧F ⊕ C111110∧A∧B∧C∧D∧E ⊕ C111101∧A∧B∧C∧D∧F ⊕ C111011∧A∧B∧C∧E∧F ⊕ C110111∧A∧B∧D∧E∧F ⊕ C101111∧A∧C∧D∧E∧F ⊕ C011111∧B∧C∧D∧E∧F ⊕ C111111∧A∧B∧C∧D∧E∧F

Так как Fж(000000) = 0, то С000000 = 0.

Далее подставляем все остальные наборы в порядке возрастания числа единиц, подставляя вновь полученные значения в следующие формулы:
Fж(100000) = С000000 ⊕ С100000 = 0 => С100000 = 0 ⊕ 0 = 0
Fж(010000) = С000000 ⊕ С010000 = 0 => С010000 = 0 ⊕ 0 = 0
Fж(001000) = С000000 ⊕ С001000 = 0 => С001000 = 0 ⊕ 0 = 0
Fж(000100) = С000000 ⊕ С000100 = 0 => С000100 = 0 ⊕ 0 = 0
Fж(000010) = С000000 ⊕ С000010 = 0 => С000010 = 0 ⊕ 0 = 0
Fж(000001) = С000000 ⊕ С000001 = 0 => С000001 = 0 ⊕ 0 = 0
Fж(110000) = С000000 ⊕ С100000 ⊕ С010000 ⊕ С110000 = 0 => С110000 = 0 ⊕ 0 ⊕ 0 ⊕ 0 = 0
Fж(101000) = С000000 ⊕ С100000 ⊕ С001000 ⊕ С101000 = 0 => С101000 = 0 ⊕ 0 ⊕ 0 ⊕ 0 = 0
Fж(100100) = С000000 ⊕ С100000 ⊕ С000100 ⊕ С100100 = 0 => С100100 = 0 ⊕ 0 ⊕ 0 ⊕ 0 = 0
Fж(100010) = С000000 ⊕ С100000 ⊕ С000010 ⊕ С100010 = 0 => С100010 = 0 ⊕ 0 ⊕ 0 ⊕ 0 = 0
Fж(100001) = С000000 ⊕ С100000 ⊕ С000001 ⊕ С100001 = 0 => С100001 = 0 ⊕ 0 ⊕ 0 ⊕ 0 = 0
Fж(011000) = С000000 ⊕ С010000 ⊕ С001000 ⊕ С011000 = 0 => С011000 = 0 ⊕ 0 ⊕ 0 ⊕ 0 = 0
Fж(010100) = С000000 ⊕ С010000 ⊕ С000100 ⊕ С010100 = 0 => С010100 = 0 ⊕ 0 ⊕ 0 ⊕ 0 = 0
Fж(010010) = С000000 ⊕ С010000 ⊕ С000010 ⊕ С010010 = 0 => С010010 = 0 ⊕ 0 ⊕ 0 ⊕ 0 = 0
Fж(010001) = С000000 ⊕ С010000 ⊕ С000001 ⊕ С010001 = 0 => С010001 = 0 ⊕ 0 ⊕ 0 ⊕ 0 = 0
Fж(001100) = С000000 ⊕ С001000 ⊕ С000100 ⊕ С001100 = 0 => С001100 = 0 ⊕ 0 ⊕ 0 ⊕ 0 = 0
Fж(001010) = С000000 ⊕ С001000 ⊕ С000010 ⊕ С001010 = 0 => С001010 = 0 ⊕ 0 ⊕ 0 ⊕ 0 = 0
Fж(001001) = С000000 ⊕ С001000 ⊕ С000001 ⊕ С001001 = 0 => С001001 = 0 ⊕ 0 ⊕ 0 ⊕ 0 = 0
Fж(000110) = С000000 ⊕ С000100 ⊕ С000010 ⊕ С000110 = 0 => С000110 = 0 ⊕ 0 ⊕ 0 ⊕ 0 = 0
Fж(000101) = С000000 ⊕ С000100 ⊕ С000001 ⊕ С000101 = 0 => С000101 = 0 ⊕ 0 ⊕ 0 ⊕ 0 = 0
Fж(000011) = С000000 ⊕ С000010 ⊕ С000001 ⊕ С000011 = 0 => С000011 = 0 ⊕ 0 ⊕ 0 ⊕ 0 = 0
Fж(111000) = С000000 ⊕ С100000 ⊕ С010000 ⊕ С001000 ⊕ С110000 ⊕ С101000 ⊕ С011000 ⊕ С111000 = 1 => С111000 = 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 1 = 1
Fж(110100) = С000000 ⊕ С100000 ⊕ С010000 ⊕ С000100 ⊕ С110000 ⊕ С100100 ⊕ С010100 ⊕ С110100 = 0 => С110100 = 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 = 0
Fж(110010) = С000000 ⊕ С100000 ⊕ С010000 ⊕ С000010 ⊕ С110000 ⊕ С100010 ⊕ С010010 ⊕ С110010 = 0 => С110010 = 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 = 0
Fж(110001) = С000000 ⊕ С100000 ⊕ С010000 ⊕ С000001 ⊕ С110000 ⊕ С100001 ⊕ С010001 ⊕ С110001 = 0 => С110001 = 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 = 0
Fж(101100) = С000000 ⊕ С100000 ⊕ С001000 ⊕ С000100 ⊕ С101000 ⊕ С100100 ⊕ С001100 ⊕ С101100 = 0 => С101100 = 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 = 0
Fж(101010) = С000000 ⊕ С100000 ⊕ С001000 ⊕ С000010 ⊕ С101000 ⊕ С100010 ⊕ С001010 ⊕ С101010 = 0 => С101010 = 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 = 0
Fж(101001) = С000000 ⊕ С100000 ⊕ С001000 ⊕ С000001 ⊕ С101000 ⊕ С100001 ⊕ С001001 ⊕ С101001 = 0 => С101001 = 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 = 0
Fж(100110) = С000000 ⊕ С100000 ⊕ С000100 ⊕ С000010 ⊕ С100100 ⊕ С100010 ⊕ С000110 ⊕ С100110 = 0 => С100110 = 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 = 0
Fж(100101) = С000000 ⊕ С100000 ⊕ С000100 ⊕ С000001 ⊕ С100100 ⊕ С100001 ⊕ С000101 ⊕ С100101 = 0 => С100101 = 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 = 0
Fж(100011) = С000000 ⊕ С100000 ⊕ С000010 ⊕ С000001 ⊕ С100010 ⊕ С100001 ⊕ С000011 ⊕ С100011 = 0 => С100011 = 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 = 0
Fж(011100) = С000000 ⊕ С010000 ⊕ С001000 ⊕ С000100 ⊕ С011000 ⊕ С010100 ⊕ С001100 ⊕ С011100 = 0 => С011100 = 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 = 0
Fж(011010) = С000000 ⊕ С010000 ⊕ С001000 ⊕ С000010 ⊕ С011000 ⊕ С010010 ⊕ С001010 ⊕ С011010 = 0 => С011010 = 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 = 0
Fж(011001) = С000000 ⊕ С010000 ⊕ С001000 ⊕ С000001 ⊕ С011000 ⊕ С010001 ⊕ С001001 ⊕ С011001 = 0 => С011001 = 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 = 0
Fж(010110) = С000000 ⊕ С010000 ⊕ С000100 ⊕ С000010 ⊕ С010100 ⊕ С010010 ⊕ С000110 ⊕ С010110 = 0 => С010110 = 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 = 0
Fж(010101) = С000000 ⊕ С010000 ⊕ С000100 ⊕ С000001 ⊕ С010100 ⊕ С010001 ⊕ С000101 ⊕ С010101 = 0 => С010101 = 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 = 0
Fж(010011) = С000000 ⊕ С010000 ⊕ С000010 ⊕ С000001 ⊕ С010010 ⊕ С010001 ⊕ С000011 ⊕ С010011 = 0 => С010011 = 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 = 0
Fж(001110) = С000000 ⊕ С001000 ⊕ С000100 ⊕ С000010 ⊕ С001100 ⊕ С001010 ⊕ С000110 ⊕ С001110 = 0 => С001110 = 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 = 0
Fж(001101) = С000000 ⊕ С001000 ⊕ С000100 ⊕ С000001 ⊕ С001100 ⊕ С001001 ⊕ С000101 ⊕ С001101 = 0 => С001101 = 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 = 0
Fж(001011) = С000000 ⊕ С001000 ⊕ С000010 ⊕ С000001 ⊕ С001010 ⊕ С001001 ⊕ С000011 ⊕ С001011 = 0 => С001011 = 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 = 0
Fж(000111) = С000000 ⊕ С000100 ⊕ С000010 ⊕ С000001 ⊕ С000110 ⊕ С000101 ⊕ С000011 ⊕ С000111 = 0 => С000111 = 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 = 0
Fж(111100) = С000000 ⊕ С100000 ⊕ С010000 ⊕ С001000 ⊕ С000100 ⊕ С110000 ⊕ С101000 ⊕ С100100 ⊕ С011000 ⊕ С010100 ⊕ С001100 ⊕ С111000 ⊕ С110100 ⊕ С101100 ⊕ С011100 ⊕ С111100 = 1 => С111100 = 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 1 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 1 = 0
Fж(111010) = С000000 ⊕ С100000 ⊕ С010000 ⊕ С001000 ⊕ С000010 ⊕ С110000 ⊕ С101000 ⊕ С100010 ⊕ С011000 ⊕ С010010 ⊕ С001010 ⊕ С111000 ⊕ С110010 ⊕ С101010 ⊕ С011010 ⊕ С111010 = 1 => С111010 = 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 1 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 1 = 0
Fж(111001) = С000000 ⊕ С100000 ⊕ С010000 ⊕ С001000 ⊕ С000001 ⊕ С110000 ⊕ С101000 ⊕ С100001 ⊕ С011000 ⊕ С010001 ⊕ С001001 ⊕ С111000 ⊕ С110001 ⊕ С101001 ⊕ С011001 ⊕ С111001 = 1 => С111001 = 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 1 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 1 = 0
Fж(110110) = С000000 ⊕ С100000 ⊕ С010000 ⊕ С000100 ⊕ С000010 ⊕ С110000 ⊕ С100100 ⊕ С100010 ⊕ С010100 ⊕ С010010 ⊕ С000110 ⊕ С110100 ⊕ С110010 ⊕ С100110 ⊕ С010110 ⊕ С110110 = 0 => С110110 = 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 = 0
Fж(110101) = С000000 ⊕ С100000 ⊕ С010000 ⊕ С000100 ⊕ С000001 ⊕ С110000 ⊕ С100100 ⊕ С100001 ⊕ С010100 ⊕ С010001 ⊕ С000101 ⊕ С110100 ⊕ С110001 ⊕ С100101 ⊕ С010101 ⊕ С110101 = 0 => С110101 = 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 = 0
Fж(110011) = С000000 ⊕ С100000 ⊕ С010000 ⊕ С000010 ⊕ С000001 ⊕ С110000 ⊕ С100010 ⊕ С100001 ⊕ С010010 ⊕ С010001 ⊕ С000011 ⊕ С110010 ⊕ С110001 ⊕ С100011 ⊕ С010011 ⊕ С110011 = 0 => С110011 = 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 = 0
Fж(101110) = С000000 ⊕ С100000 ⊕ С001000 ⊕ С000100 ⊕ С000010 ⊕ С101000 ⊕ С100100 ⊕ С100010 ⊕ С001100 ⊕ С001010 ⊕ С000110 ⊕ С101100 ⊕ С101010 ⊕ С100110 ⊕ С001110 ⊕ С101110 = 0 => С101110 = 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 = 0
Fж(101101) = С000000 ⊕ С100000 ⊕ С001000 ⊕ С000100 ⊕ С000001 ⊕ С101000 ⊕ С100100 ⊕ С100001 ⊕ С001100 ⊕ С001001 ⊕ С000101 ⊕ С101100 ⊕ С101001 ⊕ С100101 ⊕ С001101 ⊕ С101101 = 0 => С101101 = 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 = 0
Fж(101011) = С000000 ⊕ С100000 ⊕ С001000 ⊕ С000010 ⊕ С000001 ⊕ С101000 ⊕ С100010 ⊕ С100001 ⊕ С001010 ⊕ С001001 ⊕ С000011 ⊕ С101010 ⊕ С101001 ⊕ С100011 ⊕ С001011 ⊕ С101011 = 0 => С101011 = 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 = 0
Fж(100111) = С000000 ⊕ С100000 ⊕ С000100 ⊕ С000010 ⊕ С000001 ⊕ С100100 ⊕ С100010 ⊕ С100001 ⊕ С000110 ⊕ С000101 ⊕ С000011 ⊕ С100110 ⊕ С100101 ⊕ С100011 ⊕ С000111 ⊕ С100111 = 0 => С100111 = 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 = 0
Fж(011110) = С000000 ⊕ С010000 ⊕ С001000 ⊕ С000100 ⊕ С000010 ⊕ С011000 ⊕ С010100 ⊕ С010010 ⊕ С001100 ⊕ С001010 ⊕ С000110 ⊕ С011100 ⊕ С011010 ⊕ С010110 ⊕ С001110 ⊕ С011110 = 0 => С011110 = 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 = 0
Fж(011101) = С000000 ⊕ С010000 ⊕ С001000 ⊕ С000100 ⊕ С000001 ⊕ С011000 ⊕ С010100 ⊕ С010001 ⊕ С001100 ⊕ С001001 ⊕ С000101 ⊕ С011100 ⊕ С011001 ⊕ С010101 ⊕ С001101 ⊕ С011101 = 0 => С011101 = 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 = 0
Fж(011011) = С000000 ⊕ С010000 ⊕ С001000 ⊕ С000010 ⊕ С000001 ⊕ С011000 ⊕ С010010 ⊕ С010001 ⊕ С001010 ⊕ С001001 ⊕ С000011 ⊕ С011010 ⊕ С011001 ⊕ С010011 ⊕ С001011 ⊕ С011011 = 0 => С011011 = 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 = 0
Fж(010111) = С000000 ⊕ С010000 ⊕ С000100 ⊕ С000010 ⊕ С000001 ⊕ С010100 ⊕ С010010 ⊕ С010001 ⊕ С000110 ⊕ С000101 ⊕ С000011 ⊕ С010110 ⊕ С010101 ⊕ С010011 ⊕ С000111 ⊕ С010111 = 0 => С010111 = 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 = 0
Fж(001111) = С000000 ⊕ С001000 ⊕ С000100 ⊕ С000010 ⊕ С000001 ⊕ С001100 ⊕ С001010 ⊕ С001001 ⊕ С000110 ⊕ С000101 ⊕ С000011 ⊕ С001110 ⊕ С001101 ⊕ С001011 ⊕ С000111 ⊕ С001111 = 0 => С001111 = 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 = 0
Fж(111110) = С000000 ⊕ С100000 ⊕ С010000 ⊕ С001000 ⊕ С000100 ⊕ С000010 ⊕ С110000 ⊕ С101000 ⊕ С100100 ⊕ С100010 ⊕ С011000 ⊕ С010100 ⊕ С010010 ⊕ С001100 ⊕ С001010 ⊕ С000110 ⊕ С111000 ⊕ С110100 ⊕ С110010 ⊕ С101100 ⊕ С101010 ⊕ С100110 ⊕ С011100 ⊕ С011010 ⊕ С010110 ⊕ С001110 ⊕ С111100 ⊕ С111010 ⊕ С110110 ⊕ С101110 ⊕ С011110 ⊕ С111110 = 1 => С111110 = 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 1 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 1 = 0
Fж(111101) = С000000 ⊕ С100000 ⊕ С010000 ⊕ С001000 ⊕ С000100 ⊕ С000001 ⊕ С110000 ⊕ С101000 ⊕ С100100 ⊕ С100001 ⊕ С011000 ⊕ С010100 ⊕ С010001 ⊕ С001100 ⊕ С001001 ⊕ С000101 ⊕ С111000 ⊕ С110100 ⊕ С110001 ⊕ С101100 ⊕ С101001 ⊕ С100101 ⊕ С011100 ⊕ С011001 ⊕ С010101 ⊕ С001101 ⊕ С111100 ⊕ С111001 ⊕ С110101 ⊕ С101101 ⊕ С011101 ⊕ С111101 = 1 => С111101 = 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 1 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 1 = 0
Fж(111011) = С000000 ⊕ С100000 ⊕ С010000 ⊕ С001000 ⊕ С000010 ⊕ С000001 ⊕ С110000 ⊕ С101000 ⊕ С100010 ⊕ С100001 ⊕ С011000 ⊕ С010010 ⊕ С010001 ⊕ С001010 ⊕ С001001 ⊕ С000011 ⊕ С111000 ⊕ С110010 ⊕ С110001 ⊕ С101010 ⊕ С101001 ⊕ С100011 ⊕ С011010 ⊕ С011001 ⊕ С010011 ⊕ С001011 ⊕ С111010 ⊕ С111001 ⊕ С110011 ⊕ С101011 ⊕ С011011 ⊕ С111011 = 1 => С111011 = 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 1 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 1 = 0
Fж(110111) = С000000 ⊕ С100000 ⊕ С010000 ⊕ С000100 ⊕ С000010 ⊕ С000001 ⊕ С110000 ⊕ С100100 ⊕ С100010 ⊕ С100001 ⊕ С010100 ⊕ С010010 ⊕ С010001 ⊕ С000110 ⊕ С000101 ⊕ С000011 ⊕ С110100 ⊕ С110010 ⊕ С110001 ⊕ С100110 ⊕ С100101 ⊕ С100011 ⊕ С010110 ⊕ С010101 ⊕ С010011 ⊕ С000111 ⊕ С110110 ⊕ С110101 ⊕ С110011 ⊕ С100111 ⊕ С010111 ⊕ С110111 = 0 => С110111 = 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 = 0
Fж(101111) = С000000 ⊕ С100000 ⊕ С001000 ⊕ С000100 ⊕ С000010 ⊕ С000001 ⊕ С101000 ⊕ С100100 ⊕ С100010 ⊕ С100001 ⊕ С001100 ⊕ С001010 ⊕ С001001 ⊕ С000110 ⊕ С000101 ⊕ С000011 ⊕ С101100 ⊕ С101010 ⊕ С101001 ⊕ С100110 ⊕ С100101 ⊕ С100011 ⊕ С001110 ⊕ С001101 ⊕ С001011 ⊕ С000111 ⊕ С101110 ⊕ С101101 ⊕ С101011 ⊕ С100111 ⊕ С001111 ⊕ С101111 = 0 => С101111 = 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 = 0
Fж(011111) = С000000 ⊕ С010000 ⊕ С001000 ⊕ С000100 ⊕ С000010 ⊕ С000001 ⊕ С011000 ⊕ С010100 ⊕ С010010 ⊕ С010001 ⊕ С001100 ⊕ С001010 ⊕ С001001 ⊕ С000110 ⊕ С000101 ⊕ С000011 ⊕ С011100 ⊕ С011010 ⊕ С011001 ⊕ С010110 ⊕ С010101 ⊕ С010011 ⊕ С001110 ⊕ С001101 ⊕ С001011 ⊕ С000111 ⊕ С011110 ⊕ С011101 ⊕ С011011 ⊕ С010111 ⊕ С001111 ⊕ С011111 = 0 => С011111 = 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 = 0
Fж(111111) = С000000 ⊕ С100000 ⊕ С010000 ⊕ С001000 ⊕ С000100 ⊕ С000010 ⊕ С000001 ⊕ С110000 ⊕ С101000 ⊕ С100100 ⊕ С100010 ⊕ С100001 ⊕ С011000 ⊕ С010100 ⊕ С010010 ⊕ С010001 ⊕ С001100 ⊕ С001010 ⊕ С001001 ⊕ С000110 ⊕ С000101 ⊕ С000011 ⊕ С111000 ⊕ С110100 ⊕ С110010 ⊕ С110001 ⊕ С101100 ⊕ С101010 ⊕ С101001 ⊕ С100110 ⊕ С100101 ⊕ С100011 ⊕ С011100 ⊕ С011010 ⊕ С011001 ⊕ С010110 ⊕ С010101 ⊕ С010011 ⊕ С001110 ⊕ С001101 ⊕ С001011 ⊕ С000111 ⊕ С111100 ⊕ С111010 ⊕ С111001 ⊕ С110110 ⊕ С110101 ⊕ С110011 ⊕ С101110 ⊕ С101101 ⊕ С101011 ⊕ С100111 ⊕ С011110 ⊕ С011101 ⊕ С011011 ⊕ С010111 ⊕ С001111 ⊕ С111110 ⊕ С111101 ⊕ С111011 ⊕ С110111 ⊕ С101111 ⊕ С011111 ⊕ С111111 = 0 => С111111 = 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 1 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 ⊕ 0 = 1

Таким образом, полином Жегалкина будет равен:
Fж = A∧B∧C ⊕ A∧B∧C∧D∧E∧F
Логическая схема, соответствующая полиному Жегалкина:

Околостуденческое

Рейтинг@Mail.ru

© 2009-2024, Список Литературы